# What does black hole evaporation correspond to in the accelerating universe / black hole analogy?

In the same way, as a black hole emits Hawking radiation corresponding to its temperature

$$T = \frac{\hbar}{r_{BH}}$$

the accelerating universe can be described as all of the stuff falling towards the cosmic horizon, such that it is analogue to a black hole where the cosmic horizon takes the role of the event horizon with the black hole "interior" being outside.

The corresponding temperature of the accelerating universe is given by

$$T = \hbar H = \frac{\hbar}{R_{H}}$$

where H is the Hubble constant. Therefore, the cosmic horizon emits something similar to Hawking radiation too.

The fate of a black hole is to finally evaporate. My question is: What does black hole evaporation correspond to in the accelerating universe when making use of this analogy?

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Dear downvoter, what is wrong with my question, can you please be a bit more specific and explicit thant just pushing the button ? –  Dilaton Apr 21 '14 at 11:14