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Like it was already pointed out in the comments, your assertions and assumptions are way off today's well-accepted theories. Nonetheless, I'll try to answer you questions. Will our solar system die of old age in 5.4 billion years Our sun is a G-type main-sequence star with an estimated lifespan of roughly 10 billion years. Like you mentioned, it is about ...


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There may be Sednoids there. Sednoids are a hypothetical class of "inner Oort Cloud objects" named after their prototype, Sedna. Sedna's aphelion is ~936 AU, bringing it close to the inner boundary of the Oort Cloud. Sednoids may have aphelions ranging from about 100 AU to 1,000 AU. The problem is, only two Sednoids have beet detected to date, 90377 Sedna ...


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The Kuiper belt and the Scattered disk are widely believed to lie in the space between the outer planets and the Oort cloud, but not to reach all the way out to the Oort cloud (apparently due to resonances with Neptune and a scarcity of sighted object much outside the 1:2 resonance orbit). The various dwarf planets of the outer solar system are sometimes ...


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[Not sure if I should answer this, but I will try to answer something while trying hard to not go off-topic.] The planets aspects Mercury surface is essentially a collection of small random craters with no discernible pattern at all, so you might not consider which side is presented. The only distinguished feature is a set of dark craters in its north ...


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I am not very familiar with orbital dynamics (so please correct me if I'm wrong). I was told that, for instance in the case of the mean motion resonances that cause the majority of the Kirkwood gaps in the asteroid belt, not only the ratio of the periods, but also the timing is important. Let's take Pluto as an example, which is in 2:3 resonance with ...


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I am assuming that the question you want answered is how to calculate the elevation of an orbit above a reference plane given the orbital inclination with this plane. If so, please update your question to reflect this, heeding the advice given in the comments. Kepler's first law tells us that Planet's move in elliptical orbits, which we can define as ...


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As others have calculated, there are no predicted double transits. Since Venus transits for about 12 hours each hundred years (roughly), Venus is in transit for about 1/100000 of the time. Thus there is a (roughly) 1 in 100000 chance that a randomly chosen transit of mercury will coincide with a transit of Venus. Since Transits of Mercury occur every 10 ...


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EDIT: As it turns out, I'm not the first or even the second person to run calculations like this: https://www.fourmilab.ch/documents/canon_transits/ http://www.solexorb.it/SolexOld/Simtrans.pdf Meeus' work (second link) mentions the 13425 CE event in "Table 1. Simultaneous and near-simultaneous transits of Mercury and Venus, years 1 to 300,000" Within ...


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It is listed in this wikipedia page. Pluto's radius is listed there as 1,150 km; the radius of the barycenter is 2,110 km. So the barycenter is 960 km above Pluto's surface! (Note the radius of Pluto quoted differs to its main wikipedia page; that one says around 1,187 km)


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As StephenG stated, this is not the reason why Pluto is no longer a planet. The center of rotation of the two bodies is called the barycenter. It can be calculated with accuracy, knowing the mass of the two bodies and the distance separating them. See : The little ring around Pluto in the center describes its path. The barycenter of this binary system ...


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I know that Pluto and Charon have been found to circle round each other, hence the reason Pluto is no longer a planet This is not correct. It is considered a dwarf planet because of a technical definition employed by the IAU in deciding what is a planet and is not. This technical definition relates to an object's ability to "sweep" it's orbit clear ...



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