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The question is:

If you stand on the equator of the Moon, at midday your position occurs when the Moon is located at the line of the node. What is the altitude of the sun at that moment?

Information: This is when the Moon is located at the line of node (line of node is a line that occurs from crossing between the ecliptic plane and the Moon's orbital plane, which makes an angle of approximate 5 degrees). The equatorial plane of the Sun makes an angle of 1 degrees, 32 arc minutes and 40 arc seconds.

The solution is 88 degrees, 27 arc minutes and 20 arc seconds through 90 degrees.

But I don't understand why the answer isn't 1 degree, 32 arc minutes and 20 arc seconds, because the ecliptic plane where the sun is located is above the horizon or celestial equator. equal to its altitude.

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    $\begingroup$ Think about what your proposed answer means for a bit. Does it make any sense? (The answer is no.) Your answer means that at local noon on the Moon's equator you'll see the Sun just 1.5 degrees above the horizon. On Uranus, maybe. On the Moon? No. The Sun is 1.5 degrees shy of vertical, not 1.5 degrees above the horizon. $\endgroup$
    – David Hammen
    Jan 3, 2015 at 21:29
  • $\begingroup$ Your comment was very helpful. I understand why the altitude should be 88.5 now,but why the solution is 88.5 through 90 degrees? Isn't it should be one altitude, not in a range? $\endgroup$
    – user9686
    Jan 8, 2015 at 3:24
  • $\begingroup$ Does the line of note relate to the result in range? $\endgroup$
    – user9686
    Jan 11, 2015 at 5:47

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@DavidHammen is essentially correct. According to stellarium, the Sun gets as high as 89 58' 48":

enter image description here

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  • $\begingroup$ Your answer was very helpful,I understand why it should be around 88.5 now,but I confuse that why the solution is in range from 88.5 through 90 degrees? Does the line of node relate? $\endgroup$
    – user9686
    Jan 11, 2015 at 5:46

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