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uhoh
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Looking at the numbers and comparing to JPL Horizons, the best match is to the position of the Earth-Moon Barycenter in heliocentric coordinates. That's of course consistent with the data being labeled as: EMB, Ecliptic Heliocentric Coordinates.

If you can live with some small uncertainties due to the details of how coordinate transforms may evolve over time, I believe you can just apply some simple trigonometry. You can confirm here.

$$r = \sqrt{x^2 + y^2 + z^2}$$

$$l = tan^{-1}(y/x)$$

$$b = sin^{-1}(z/r)$$


enter image description here

Data in Question: for JD 2415021.0
position (AU):     [-0.2054467990,  0.9615310525,  0.0002141233]
velocity (AU/day): [-0.0171063024, -0.0036576954, -0.0000011815]

JPL Horizions Earth-Moon barycenter J2000 Heliocentric for JD 2415021.0
position (AU):     [-0.2054465857,  0.9615310983,  0.00021393097] 
velocity (AU/day): [-0.0171063032, -0.0036576916, -0.00000118253]

JPL Horizions Earth J2000 Heliocentric for JD 2415021.0
position (AU):     [-0.2054522688,  0.9615603123,  0.00021303115] 
velocity (AU/day): [-0.0171136285, -0.0036594066, -0.00000182603]

JPL Horizions Earth J2000 Solar System barycenter for JD 2415021.0
position (AU):     [-0.2022720210,  0.9679285296,  0.00010939456]
velocity (AU/day): [-0.0171209826, -0.0036556277, -0.00000165111]

Looking at the numbers and comparing to JPL Horizons, the best match is to the position of the Earth-Moon Barycenter in heliocentric coordinates.

If you can live with some small uncertainties due to the details of how coordinate transforms may evolve over time, I believe you can just apply some simple trigonometry. You can confirm here.

$$r = \sqrt{x^2 + y^2 + z^2}$$

$$l = tan^{-1}(y/x)$$

$$b = sin^{-1}(z/r)$$


enter image description here

Data in Question: for JD 2415021.0
position (AU):     [-0.2054467990,  0.9615310525,  0.0002141233]
velocity (AU/day): [-0.0171063024, -0.0036576954, -0.0000011815]

JPL Horizions Earth-Moon barycenter J2000 Heliocentric for JD 2415021.0
position (AU):     [-0.2054465857,  0.9615310983,  0.00021393097] 
velocity (AU/day): [-0.0171063032, -0.0036576916, -0.00000118253]

JPL Horizions Earth J2000 Heliocentric for JD 2415021.0
position (AU):     [-0.2054522688,  0.9615603123,  0.00021303115] 
velocity (AU/day): [-0.0171136285, -0.0036594066, -0.00000182603]

JPL Horizions Earth J2000 Solar System barycenter for JD 2415021.0
position (AU):     [-0.2022720210,  0.9679285296,  0.00010939456]
velocity (AU/day): [-0.0171209826, -0.0036556277, -0.00000165111]

Looking at the numbers and comparing to JPL Horizons, the best match is to the position of the Earth-Moon Barycenter in heliocentric coordinates. That's of course consistent with the data being labeled as: EMB, Ecliptic Heliocentric Coordinates.

If you can live with some small uncertainties due to the details of how coordinate transforms may evolve over time, I believe you can just apply some simple trigonometry. You can confirm here.

$$r = \sqrt{x^2 + y^2 + z^2}$$

$$l = tan^{-1}(y/x)$$

$$b = sin^{-1}(z/r)$$


enter image description here

Data in Question: for JD 2415021.0
position (AU):     [-0.2054467990,  0.9615310525,  0.0002141233]
velocity (AU/day): [-0.0171063024, -0.0036576954, -0.0000011815]

JPL Horizions Earth-Moon barycenter J2000 Heliocentric for JD 2415021.0
position (AU):     [-0.2054465857,  0.9615310983,  0.00021393097] 
velocity (AU/day): [-0.0171063032, -0.0036576916, -0.00000118253]

JPL Horizions Earth J2000 Heliocentric for JD 2415021.0
position (AU):     [-0.2054522688,  0.9615603123,  0.00021303115] 
velocity (AU/day): [-0.0171136285, -0.0036594066, -0.00000182603]

JPL Horizions Earth J2000 Solar System barycenter for JD 2415021.0
position (AU):     [-0.2022720210,  0.9679285296,  0.00010939456]
velocity (AU/day): [-0.0171209826, -0.0036556277, -0.00000165111]
Source Link
uhoh
  • 30.7k
  • 9
  • 98
  • 313

Looking at the numbers and comparing to JPL Horizons, the best match is to the position of the Earth-Moon Barycenter in heliocentric coordinates.

If you can live with some small uncertainties due to the details of how coordinate transforms may evolve over time, I believe you can just apply some simple trigonometry. You can confirm here.

$$r = \sqrt{x^2 + y^2 + z^2}$$

$$l = tan^{-1}(y/x)$$

$$b = sin^{-1}(z/r)$$


enter image description here

Data in Question: for JD 2415021.0
position (AU):     [-0.2054467990,  0.9615310525,  0.0002141233]
velocity (AU/day): [-0.0171063024, -0.0036576954, -0.0000011815]

JPL Horizions Earth-Moon barycenter J2000 Heliocentric for JD 2415021.0
position (AU):     [-0.2054465857,  0.9615310983,  0.00021393097] 
velocity (AU/day): [-0.0171063032, -0.0036576916, -0.00000118253]

JPL Horizions Earth J2000 Heliocentric for JD 2415021.0
position (AU):     [-0.2054522688,  0.9615603123,  0.00021303115] 
velocity (AU/day): [-0.0171136285, -0.0036594066, -0.00000182603]

JPL Horizions Earth J2000 Solar System barycenter for JD 2415021.0
position (AU):     [-0.2022720210,  0.9679285296,  0.00010939456]
velocity (AU/day): [-0.0171209826, -0.0036556277, -0.00000165111]