Timeline for Angular speed of a planet across the sky
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Oct 29, 2018 at 17:55 | comment | added | Fattie | I don't really follow that! | |
| Oct 29, 2018 at 17:24 | vote | accept | Brasil | ||
| Oct 29, 2018 at 13:31 | history | edited | Brasil | CC BY-SA 4.0 |
added 38 characters in body
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| Oct 29, 2018 at 13:16 | comment | added | Brasil | Hi, @JamesK. Yes, I am doing simplified calculations assuming circular orbits just for the sake of visualization of the configurations. More precise calculus would require Kepler's laws analysis. Here, the Earth is not stationary, but the frame of reference to calculate the speed $\dot{\theta}$. I will edit the answer to make it clear that the speed $\dot{\psi}$ is actually the one associated to the synodic period of the planet. Thank you! | |
| Oct 29, 2018 at 13:12 | history | edited | Brasil | CC BY-SA 4.0 |
added 38 characters in body
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| Oct 28, 2018 at 8:51 | comment | added | James K | This appears to assume that the Earth is stationary. Are you doing the calculations in a rotating frame of reference? Should D be the Earth-planet distance? Are you assuming circular orbits ( a good approximation for Venus, less good for Mercury) | |
| Oct 27, 2018 at 23:05 | history | edited | Brasil | CC BY-SA 4.0 |
added 62 characters in body
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| Oct 27, 2018 at 22:55 | history | edited | Brasil | CC BY-SA 4.0 |
added 62 characters in body
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| S Oct 27, 2018 at 22:37 | history | suggested | Tosic | CC BY-SA 4.0 |
Changed formatting to LaTeX
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| Oct 27, 2018 at 21:52 | review | Suggested edits | |||
| S Oct 27, 2018 at 22:37 | |||||
| Oct 27, 2018 at 17:17 | history | answered | Brasil | CC BY-SA 4.0 |