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ProfRob
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The unit is that of a velocity. If you have bins of equal $\Delta \ln \lambda$$\ln \lambda$ (which equals $\Delta \lambda/\lambda =\Delta v/c$), then each of your pixels (in your spectrum and in the template) representsrepresents a constant velocity increment $\Delta v = c |\Delta \ln \lambda|$, which could have units of km/s.

The shift in the peak of a cross-correlation function is known as "the lag" and the velocity shift is given by the lag (in pixels) multiplied by $\Delta v$.

The unit is that of a velocity. If you have bins of equal $\Delta \ln \lambda$, then each of your pixels (in your spectrum and in the template) represents a constant velocity increment $\Delta v = c |\Delta \ln \lambda|$, which could have units of km/s.

The shift in the peak of a cross-correlation function is known as "the lag" and the velocity shift is given by the lag (in pixels) multiplied by $\Delta v$.

The unit is that of a velocity. If you have bins of equal $\ln \lambda$ (which equals $\Delta \lambda/\lambda =\Delta v/c$), then each of your pixels (in your spectrum and in the template) represents a constant velocity increment $\Delta v = c |\Delta \ln \lambda|$, which could have units of km/s.

The shift in the peak of a cross-correlation function is known as "the lag" and the velocity shift is given by the lag (in pixels) multiplied by $\Delta v$.

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ProfRob
  • 162.7k
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  • 389
  • 615

The unit is that of a velocity. If you have bins of equal $\Delta \ln \lambda$, then each of your pixels (in your spectrum and in the template) represents a constant velocity increment $\Delta v = c |\Delta \ln \lambda|$, which could have units of km/s.

The shift in the peak of a cross-correlation function is known as "the lag" and the velocity shift is given by the lag (in pixels) multiplied by $\Delta v$.

The unit is that of a velocity. If you have bins of equal $\Delta \ln \lambda$, then each of your pixels represents a constant velocity increment $\Delta v = c |\Delta \ln \lambda|$, which could have units of km/s.

The shift in the peak of a cross-correlation function is known as "the lag" and the velocity shift is given by the lag (in pixels) multiplied by $\Delta v$.

The unit is that of a velocity. If you have bins of equal $\Delta \ln \lambda$, then each of your pixels (in your spectrum and in the template) represents a constant velocity increment $\Delta v = c |\Delta \ln \lambda|$, which could have units of km/s.

The shift in the peak of a cross-correlation function is known as "the lag" and the velocity shift is given by the lag (in pixels) multiplied by $\Delta v$.

Source Link
ProfRob
  • 162.7k
  • 10
  • 389
  • 615

The unit is that of a velocity. If you have bins of equal $\Delta \ln \lambda$, then each of your pixels represents a constant velocity increment $\Delta v = c |\Delta \ln \lambda|$, which could have units of km/s.

The shift in the peak of a cross-correlation function is known as "the lag" and the velocity shift is given by the lag (in pixels) multiplied by $\Delta v$.