# Orbits in a binary star system

I know of three sets of stable orbits in a binary star system: orbiting closely around star A, orbiting closely around star B, or orbiting distantly around both stars (and their mutual center of gravity) at once.

Is there a fourth set of stable orbits, around the mutual center of gravity, but inside both stars' orbits?

• Can you draw a picture of what this would look like? Jul 26 '15 at 13:25
– Mark
Jul 26 '15 at 19:45
• I strongly suspect that's not stable long term, even though the planet does orbit the 2 stars center of gravity. I find it hard to believe that wouldn't rather quickly destabilize. There's a handful of calculated 3 body scenarios that work, my favorite is the figure 8 (this one is 3 equal bodies) ams.org/featurecolumn/images/simo03.gif and more here: news.sciencemag.org/physics/2013/03/…. Your question is slightly different, but I still feel pretty confident in saying that wouldn't be stable for long. Jul 27 '15 at 8:15
• You can't have an orbit like that. There is no force toward the barycenter. This planet would be shot out of the binary system at high speed in no time flat. Jul 28 '15 at 18:26

The point you appear to refer to, is called the Lagrangian point $L_1$. This point is a saddle in the field of gravity, hence not to be considered to be stable in the strict sense. Two other Lagrangian points, called $L_4$ and $L_5$, can be stable, provided the considered orbiting objects are of small mass in comparison to the two main bodies of the system, and if the masses of the binary components are sufficiently different.
According to theorem 4.1 of this paper, $L_4$ and $L_5$ are stable in all directions, if and only if the mass ratio of the two main binary components $\frac{m_1}{m_2}\geq\frac{25+3\sqrt{69}}{2}\approx 24.9599$. According to theorem 3.1 of the same paper all Lagrangian points are stable in z-direction, which is the direction perpendicular to the orbital plane of the binary system. (Credits for this corrected version go to user DylanSp.)
• @Gerald According to these notes from NASA, the ratio between $M_1$ and $M_2$ also needs to be sufficiently high for $L_4$ and $L_5$ need to be stable. Your source doesn't go into sufficient detail on the conditions for stability of $L_4$ and $L_5$. Mar 3 '16 at 18:56