2
$\begingroup$

"A few minutes into the expansion, when the temperature was about a billion (one thousand million) kelvin and the density was about that of air, neutrons combined with protons to form the universe's deuterium and helium nuclei in a process called Big Bang nucleosynthesis. Most protons remained uncombined as hydrogen nuclei. As the universe cooled, the rest mass energy density of matter came to gravitationally dominate that of the photon radiation.

After about 379,000 years the electrons and nuclei combined into atoms (mostly hydrogen); hence the radiation decoupled from matter and continued through space largely unimpeded. This relic radiation is known as the cosmic microwave background radiation."

The question now is, when you count back starting with the cosmic background radiation which is now in far red (2,7K) at what time was there for the first time visible light, or was is right after the creation of atoms about 379,000 after the big bang?

$\endgroup$
1
  • $\begingroup$ Can you give a source for the quote? I suspect Wikipedia. Thanks. $\endgroup$
    – HDE 226868
    Feb 21, 2016 at 23:09

2 Answers 2

4
$\begingroup$

The best model we have is that of electro-weak unification.

The photon is an quantum of the electromagnetic field, and as long as there has been an electromagnetic field, excitation of the field have existed.

The "weak" nuclear interaction is another field, (it has the effect of changing up quarks to down quarks, and so is responsible for beta decay of radioactive material). Quanta of the weak field are rather different from photons. They are charged and have mass, but at very high energies (a million billion degrees or so) the electromagnetic and weak fields are unified into a single "electroweak" interaction.

But after the universe had cooled (it took sometime between $10^{-36}$ and $10^{-32}$ seconds) the weak and electromagnetic fields split, and the first true photons formed.

These photons didn't get very far before colliding with other particles that were being formed. As you note, it took nearly 400000 years until the universe cooled enough to become transparent.

Now you mention visible light. The photons formed after the split would have had very high energies, we would call most of them gamma rays if they existed today. But as photon of all energies could be formed, a small fraction would have been in the visible range.

At recombination, when the universe became transparent, the temperature was about 3000K, at which temperature most photons are in the infra red range, but enough are visible to have given the universe a very bright orange-red colour, similar to the colour of a lightbulb.

$\endgroup$
2
$\begingroup$

To expand a bit on James Kilfiger's great answer:

The peak wavelength of the cosmic microwave background

The wavelength of the cosmic microwave background (as well as any other photon) is stretched proportionally to the scale factor $a(t) = 1/(1+z)$ ("the size") of the Universe, where $t$ is the age of the Universe and $z$ is the redshift of light emitted at $t$ and observed today. Thus, at redshift $z$ the peak of the CMB spectrum was lying at a wavelength $$ \lambda_\mathrm{max}(z) = \frac{\lambda_\mathrm{max,0}}{1+z}. $$

Today, the CMB spectrum peaks at $\lambda_\mathrm{max,0} \simeq 0.2\,\mathrm{cm}$. If we take visible light to lie in the range 400-700 nm, the maximum of the CMB spectrum must have been in the visible range at redshifts $$ z \,\,=\,\, \frac{\lambda_\mathrm{max,0}}{\lambda_\mathrm{max}(z)} - 1 \,\,=\,\, \frac{0.2\,\mathrm{nm}}{\{4\,\verb+-+\,7\}\times10^{-5}\,\mathrm{nm}} - 1 \,\,\sim\,\, \{2700\,\verb+-+\,4700\}. $$ This can be converted to an age of the Universe by integrating (numerically) the Friedmann equation. Assuming a Planck 2015 cosmology, I get that the peak of the CMB spectrum was in the visible range when the Universe was between roughly 50,000 and 125,000 years old.

The color of the Universe

However, as James Kilfiger also mentions, even though the peak lies outside the visible range, a fraction of the spectrum is still inside. Its color depends on the response of the cones of the human eye and follows approximately the so-called Planckian locus in the CIE 1931 color space:

ColorTemp

In the plot above, the locus traces the color of the Universe as a function of temperature (thin numbers), and age of the Universe in kiloyears (kyr; bold numbers).

That is, the Universe started out as bluish (when $T\gtrsim10^4\,\mathrm{K}$), became whitish at an age of around 200,000 years (when $T\sim5\verb+-+6000\,\mathrm{K}$), and then gradually went over orange and red at $t\sim1\,\mathrm{Myr}$ before fading into the infrared. This evolution is completely analogous to the colors of stars of a given temperature.

The ages have been calculated with Python's CosmoloPy.distances.age(), which I think is not very accurate at such small ages, but it does give the approximate age. Also, whether or not the CMB was visible to the naked eye — i.e. without a telescope to enlarge the light-collecting area — depends on the intensity at a given point.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .