1
$\begingroup$

Here, we are looking for a statistically significant difference between the mean redshifts of galaxies ahead and those behind, with reference to a prior-specified direction. For example, suppose that we were aboard an advanced spaceship that had been accelerating in that direction at (say) 1 $g$ for some years. How soon into our journey would we notice that the galaxies ahead were bluer than the galaxies behind? Clearly this depends on our existing model, based on prior observations, for the distribution of galaxies' redshifts, and on some reasonable kind of weighting for each individual galaxy (perhaps according to the cosine of angle from our direction of travel, but not according to the galaxy's distance). However, in this analysis, we are ignoring individual data about any particular galaxy acquired before our present observation. For simplicity, let us also suppose that there is no statistically significant difference between the mean redshifts forward and back in the line of our journey before we began it. For the sake of definiteness, if it is needed, let us take a significance level of 1%.

$\endgroup$
  • $\begingroup$ Insufficient information. How many galaxies are being observed and what is their redshift distribution? At a trivial level we can straightforwardly tell our state of motion relative to the microwave background. $\endgroup$ – Rob Jeffries Jul 31 '16 at 20:15
  • $\begingroup$ @RobJeffries: I am assuming as many galaxies observed as are in the present database, with the present level of measurement error. I was unaware that the microwave background would allow sufficiently precise measurement to do this task well. $\endgroup$ – John Bentin Jul 31 '16 at 20:30
  • $\begingroup$ Our (solar system) speed wrt the local cosmological rest frame is $369\pm0.9$ km/s from the CMB dipole anisotropy. Accelerating at 1g, you would notice this change within a few minutes. $\endgroup$ – Rob Jeffries Jul 31 '16 at 21:22
  • $\begingroup$ Thanks, @RobJeffries . Perhaps you would post this as an answer. $\endgroup$ – John Bentin Jul 31 '16 at 21:30
2
$\begingroup$

First off, I'm not going to calculate an answer to the "significance level of 1%" part. This is more a rule of thumb kind of answer.

We're moving in a spaceship and want to see

a statistically significant difference between the mean redshifts of galaxies ahead and those behind

In other words, the red- and blueshift due to our motion must exceed the peculiar motion of the individual galaxies. Cosmologists have been dealing with a very similar problem trying to measure the Hubble constant.

I remember from a cosmology class (can't find a source at the moment) that the Coma cluster is the first cluster whose redshift is dominated by the Hubble flow as opposed to peculiar motion. This is mainly due to the fact that the local group is moving towards the nearer Virgo cluster. From the above wikipedia link: Distance ca. $100 \textrm{MPc}$, apparent recession velocity ca. $7000 \textrm{km s}^{-1}$. So, at that speed, you would definitely see a systematic difference in redshift of galaxies ahead of and behind you. How long to get to that speed at constant acceleration of $10 \frac{m}{s^2}$?

\begin{equation} a = \frac{v}{t} \Rightarrow t = \frac{v}{a} = \frac{7\cdot 10^6 m s^{-1}}{10 m s^{-2}} = 7 \cdot 10^5 s \simeq 8\, \textrm{days.} \end{equation} Note that this is a worst-case scenario. People have used much closer galaxies to determine the Hubble constant. This paper's abstract says

Due to the linearity of the expansion field the Hubble constant $\textrm{H}_0$ can be found at any distance $>4.5$ Mpc.

This is all very local, so we'll just assume a Hubble constant of $\textrm{H}_0 = 70\textrm{km}\,\textrm{s}^{-1}\,\textrm{MPc}^{-1}$ (Planck says 67.8 and Riess et al. say 73.8) and calculate redshift and hence apparent recession velocity at that distance using the Hubble law

\begin{equation} v = \textrm{H}_0 \cdot d = 70\,\textrm{km}\,\textrm{s}^{-1}\,\textrm{MPc}^{-1} \cdot 4.5\, \textrm{MPc} = 315\,\textrm{km}\,\textrm{s}^{-1}\,. \end{equation} At constant acceleration of 1g you'd get to that speed in about 9 hours, but you might need more time to do your data analysis on the galaxy spectra you'll have to take.

| improve this answer | |
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.