I am looking at data used in a project to get the velocity and acceleration of a CME (Coronal Mass Ejection). I understand how the velocity was calculated, and for the acceleration, I get the v2-v1 part of the formula for acceleration that was used (ex. 306.5-331.2), but what time intervals (t2-t1) were used to calculate the accelerations?

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  • $\begingroup$ Yes, strange. If you 'calculate back', a velocity change of (331.2-306.5)=24.7 resulting in an acceleration of 0.008, indicates a 51 minute period. $\endgroup$
    – user1569
    Aug 2, 2016 at 7:42

1 Answer 1


The average velocity in the interval 8:05 to 8:36 is 331.2. So, use $v_1=$ 331.2 at $t_1=$ 08:20:30 under the assumption that acceleration is constant.

The average velocity between 8:36 and 9:27 is $v_2=$ 306.5, so use $t_2=$ 9:01:30

Acceleration is $(306.5-331.3)/(41\times60)=-0.01\ $km/s$^2$.

The same calculation gives me $0.029\ $km/s$^2$ and $-0.038\ $km/s$^2$.

Is this just arithmetic error on the first value (using 51m instead of 41m), a small rounding issue on the second and the third I agree with.

Other than that, then some unstated alternative interpolation scheme has been used.


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