8
$\begingroup$

This diagram from wikipedia (shown below) graphs asteroid Diameter against Number of asteroids, for the Solar System. (Graphic is courtesy of the Marco Colombo, DensityDesign Research Lab).

Presumably the Diameter data for the larger asteroids is strongly supported by observations. But for progressively smaller bodies direct observational data is presumably less available.

The pattern shows a strong, but not perfect, linear inverse correlation between log(Diameter ) and log(Number). This seems quite reasonable for large bodies. It also sounds plausible that such a pattern continues into the realm of small asteroids and meteoroids.

But what is the physical justification for extending the log:log pattern into the realm of small bodies which are too small to see from Earth? Presumably the current estimate of the total mass of the Astroid Belt (4% of the mass of the Moon) is consistent with this distribution model. But can we confidently rule out the possibility that the linear log:log pattern breaks down for small objects allowing, for example, a much larger number (and mass) of small bodies to be present in the Asteroid Belt, sufficient say for the total combined mass to equal 100% of our Moon's mass?

enter image description here

$\endgroup$
  • 1
    $\begingroup$ When there's nothing else to go on, extrapolation is about the only tool there is. You are correct that one should be aware of exactly what assumptions were made in generating the predictions. $\endgroup$ – Carl Witthoft Oct 12 '17 at 13:26
  • 1
    $\begingroup$ I suspect that if there was that much "extra" mass in the asteroid belt, it would have been detected either from excess infrared in the ecliptic or by its dynamical effect on the orbit of Mars or other planets. Could not say to what extent these provide "upper bounds" on total asteroid belt mass. $\endgroup$ – antlersoft Oct 12 '17 at 15:14
  • $\begingroup$ @antlersoft. Thanks. I can see that a significant extra mass in the Asteroid Belt would have effect on the "precession" (rotation of the aspides) of planetary orbits but I don't have a quantitative formula. $\endgroup$ – steveOw Oct 12 '17 at 19:19
8
$\begingroup$

Your question body is different from your question title and it seems you really want to ask what you did in the question body so I'll address that.


Short Answer: The simple power law which applies for larger asteroids and comets actually doesn't extend that well to smaller bodies and shouldn't be trusted too much in that range.

Long Answer:

You're right to be suspicious of using a simple power law to relate asteroid size to quantity at small sizes. Especially because there are known deviations from that power law at certain radii. As wikipedia notes:

The number of asteroids decreases markedly with size. Although this generally follows a power law, there are 'bumps' at 5 km and 100 km, where more asteroids than expected from a logarithmic distribution are found.

Who's to say there aren't other bumps or deviations at radii that we can't observationally confirm. Our confidence in any power law's applicability for small asteroids and comets basically comes from modelling.

This power law you're asking about is essentially something referred to as an "Initial Mass Function" (IMF). A lot of work has been done to define an IMF for stars, relating the mass of stars to the number of stars at that mass. This stellar IMF follows a power law more or less, but strongly deviates for very low masses. At the surface, it would be reasonable to assume an IMF for asteroids and comets likewise deviates.

The way you answer this, is through models. See for example Cuzzi, Hogan, and Bottke (2010) (that link is to the formal journal paper, but for some reason some plots are obscured so you can also look at their "unofficial" arxiv version). In this paper, the authors attempt to construct a representative asteroid/comet population by modeling their formation via accretion of protoplanetary dust grains into asteroids, comets, KBO, and planetesimals. They make certain assumptions about the initial gas disk around the Sun and bake in physics of how these dust grains formed into larger conglomerates. Their end goal is to produce an IMF that identifies how many asteroids/comets exist at a given size. They back up a lot of their modelling with data from observations so they stick to reality as much as possible.

I'll let you peruse their results since they actually produce many different IMFs using a variety of different assumptions and starting conditions. However, I think one can summarize their results in a way which addresses your main question. As they state it:

Asteroids were born big

What they mean is that asteroids (and comets), rather than forming by successive growth via accretion of many small particles, seem to just clump together into larger bodies, completely bypassing the formation of many smaller meter-sized asteroids and comets (that's not to say there aren't meter-sized objects). You can actually see this in their various plots (fig. 4 for example). Much like the stellar IMF, the power law drastically changes once you get to small sizes and the power law which applied for larger sizes is no longer applicable. At which size the general power law no longer becomes applicable depends upon certain tunable parameters. Cuzzi et al. shows many different results with their tunable parameters set to many different possible values.

$\endgroup$
  • $\begingroup$ Great answer thanks. Yes sorry my question was garbled. Your summary and the Cuzzi paper are very informative about how the actual size/mass distribution might have evolved. Following antlersoft's comment to my question I realize that estimation of the actual present Total mass of an Asteroid Belt is based on dynamic gravitational influences rather than on models of small body size/mass distributions. And the mass of smaller unobserved material is merely the difference between that Total mass and the estimated masses of the observed bodies. $\endgroup$ – steveOw Oct 12 '17 at 19:52

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.