2
$\begingroup$

I have been researching this on google, and I think there is a process. What is this process called? I have forgotten.

$\endgroup$
  • $\begingroup$ Supernova doesn't leave what behind? Or do you mean a supernova is not left behind? More info would be nice. I don't understand what you are asking. Maybe someone else will. $\endgroup$ – jmh Dec 25 '17 at 0:02
  • $\begingroup$ i fixed it. It's where a supernova leaves nothing behind. $\endgroup$ – ElectricSupernova Dec 25 '17 at 0:12
4
$\begingroup$

You are probably thinking of a pair-instability supernova. Such a supernova releases more energy than the star's gravitational binding energy, completely disrupting the star and dispersing the contents. Meaning that with nothing else in the universe, over infinite time every particle from the star will get infinitely far away from any/every other particle. The mass, energy, etc. of the star doesn't vanish from the universe, though; it just gets spread throughout it. But there will be no dense remnant left behind: no dwarf, no neutron star, no black hole; over long time scales there won't even be a discernible nebula remaining (though note the star may have shed off significant amounts of material prior to this event, which would interact with the ejecta and may result in some sort of permanent structure suggesting a star used to be there).

$\endgroup$
  • $\begingroup$ Yes! That was it. $\endgroup$ – ElectricSupernova Dec 25 '17 at 14:18

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.