How deep in Mars' surface would one have to go to both not need a pressurized suit and be warm enough to just wear clothes? in other words is there a dept Goldilocks where you would only need an oxygen supply?

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    $\begingroup$ Very similar question: astronomy.stackexchange.com/questions/14871/… There's no sweet spot. Digging into the ground warms faster than the added weight of the atmosphere above you pressurizes. Mars doesn't have enough atmosphere for the sweet spot to exist. $\endgroup$
    – userLTK
    Commented Aug 7, 2018 at 10:28
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    $\begingroup$ I've edited my answer there to mention the temperature. $\endgroup$
    – James K
    Commented Aug 9, 2018 at 10:19
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    $\begingroup$ Not a dupe: this question asks for temperature, that question asks from pressure. $\endgroup$
    – peterh
    Commented Aug 9, 2018 at 10:41
  • $\begingroup$ It's been asked whether this question should be reopened, but the comments here and the edited answer and comments for the other question incline me to think this remains a duplicate and that reopening doesn't add value to our site. $\endgroup$ Commented Oct 27, 2018 at 23:53

1 Answer 1


According to this paper, there are various but enough good estimations for the temperature gradient of the Martian soil. Note, direct measurements will we have first with the next Martian lander, the InSight:

enter image description here

Image from here

The for us important part of this estimation is this:

Estimated Martian soil temperature gradient

Depth penetration of the annual temperature wave at $120^\circ E, > 20^\circ N$, using data from the NASA/MSFC Mars GRAM as the surface boundary condition and assuming a planetary heat flow of 20 $\frac{mW}{m^2}$. The snapshots of the temperature as a function of depth are given for the models with

  • (a) $k_\infty = 0.02 \frac{W}{m\cdot K}$ and
  • (b) $k_\infty = 0.1 \frac{W}{m\cdot K}$.

Heat flows derived from the soil temperatures given in Figures 3a and 3b for models with * (c) $k_\infty = 0.02 \frac{W}{m\cdot K}$ and * (d) $k_\infty = 0.1 \frac{W}{m\cdot K}$.

The snapshots (gray lines) show the local heat flow. The area inside the envelope (black lines) represents possible heat flow values that can be obtained by a single measurement. The heat flows derived from the annual mean temperatures are indicated by squares. Note that in order to calculate heat flows, the thermal conductivity was assumed to be known.

What we can see here, is similar to the Earth:

  • there are significant temperature differences in the upper soil, depending on the geographical position, yearly and daily cycles
  • however, around from 4m depth, the soil temperature is roughly constant.

Extrapolating the upper two graphs, we can expect a pleasant earth-like temperature not very deeply, roughly around 20-40 m.

However, according to this answer, the Earth-like pressure happens much deeper, around 20-40 km below the surface. This answer uses the Barometric formula to calculate the required depth, which is a very good estimation. It seems probably unreachable with the current technology, although it is not very far away from it: the main problems of the digging of deep holes are

  1. cooling
  2. water incursions

The first is much easier, the second is non-existant on the Mars.

Note, the Martian atmosphere is mainly carbon dioxide, thus spacesuits won't be needed, but some oxygen tanks still will be.

There is no such depth where both the temperature and the pressure would be comfortable for us.

P.s. actually, 16% pure oxygen is already enough for us to breathe, which makes the required depth to around 10-15 km.


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