Imagine a neutron star could be broke into pieces.
How big would be the piece matching Earth's mass?
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Sign up to join this communityImagine a neutron star could be broke into pieces.
How big would be the piece matching Earth's mass?
The question has no answer. The minimum mass for stable neutron matter is about 0.1 solar masses (see my answer here) and so is much more massive than the Earth.
As neutron stars become less massive they also become less dense, so your question is unanswerable at that level too, since we cannot put a figure on the density of something that cannot even exist in principle.
If your question is merely what radius is a spherical object that has a similar density to a typical neutron star, can you not do $$\frac{4\pi r^3}{3} \rho = M_{\rm Earth}$$ to find $r$?
Volume is mass divided by density.
Earth's mass = 5.972x10²⁴ kg.
Neutron star's density = 10¹⁷ kg/m³.
The sought volume of a neutron star's piece with Earth's mass is then Earth's mass divided by neutron star's density, which makes 59720000 m³. This is a cube with the side length of 390.87 m or a sphere with radius of 242.48 m.