The path of the Earth around the sun is described as being an ellipse, with the Sun being at one of the foci of the ellipse.

Since an ellipse, by definition, is symmetrical with respect to the foci, I would expect the time for the earth to transit any two halves of the ellipse to be the same, so long as it moves at the same speed around the ellipse, or at least the speed characteristics are symmetrical as well.

However, this does not appear to be the case according to the following rounded figures for the time in days between equinoxes and solstices:

Summer Solstice to Winter Solstice    181.0
Winter Solstice to Summer Solstice    184.3
Vernal Equinox to Autumnal Equinox    186.4
Autumnal Equinox to Vernal Equinox    178.9

These values can be found, for example, in astronomer Robert Newton's book of 1976.

Why are the values different?

  • $\begingroup$ Side note: use the "equal areas in equal time" law to check the elapsed time along any portion of the orbit. In any case, I think Glorfindel's answer hits it. $\endgroup$ – Carl Witthoft Oct 17 '18 at 17:27

This is because the summer and winter solstices (approx. June 21st and December 21st) do not correspond to the aphelion and perihelion (approx. July 5th and January 4th). Therefore, the average distance from the Sun is longer in the period from the Summer Solstice to Winter Solstice than vice versa, so the Earth is moving slower (on average) and it takes longer.

I think the values you mentioned are incorrect (switched around); 181.0 is a more likely value for Winter to Summer (February is a few days shorter than August).

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  • $\begingroup$ @Glorifindel, you are correct. I have a spreadsheet with all the season dates. For this year (2018) winter to next summer (2019) is 181.77 days and summer to this coming winter is 183.47 days. $\endgroup$ – BillDOe Oct 17 '18 at 19:01

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