What is the furthest star or celestial object whose distance has been calculated with parallax and how does it compare to the theoretical limit using today's telescopes? And how exactly does telescope aperture relate to the maximum distance measurable (other than the bigger the aperture the bigger the distance)?

  • $\begingroup$ Your first question is a dupe of What's the farthest object as determined only by parallax?. $\endgroup$ – pela May 1 at 10:50
  • $\begingroup$ The question is primarily about the technical limitations of that method and the theoretical limit - I hope that's enough of a difference for it not to be considered a dupe. $\endgroup$ – technical_difficulty May 1 at 10:52
  • $\begingroup$ Unclear what you mean. The best parallax precisions are discussed in answers to that question. There is no obvious "theoretical limit" to how accurately you can measure the position of an object, only technical and engineering limits that are continually being improved. We are already beyond limits where the bending of light by GR by the Sun and solar system objects must be taken account of. $\endgroup$ – Rob Jeffries May 1 at 16:43
  • $\begingroup$ See also astronomy.stackexchange.com/questions/332/… $\endgroup$ – Rob Jeffries May 1 at 16:46

Quick Google reveals a couple simple analyses. For example,

The Andromeda Galaxy, M31, is the nearest major galaxy to the Milky Way. The distance to M31 has been measured using other techniques to be 2.5⋅10^6 light years , or 7.6⋅10^5 parsecs. Using the slightly modified parallax formula, we can find the necessary parallax angle to measure the distance to Andromeda. $ p = \frac{1}{d} = > \frac{1}{7.6*10^5} parsec = 1.3 *10^{-6} arc-seconds $

This is an incredibly small angle. For comparison, the resolution of the Hubble Space Telescope is 0.05 arc-seconds, so even Hubble would not be able to detect the necessary angular shift of the nearest galaxy to effectively use parallax as a measure of its distance.

  • $\begingroup$ I think, measuring parallax does not need to measure the absolute angular position of the object on the sky. If there is an enough strong another source behind it, but enough far away, only their angle is also enough. This would enable for more better measurements. $\endgroup$ – peterh says reinstate Monica Sep 29 at 15:34

Per Wikipedia's Gaia (spacecraft); Objectives which I linked to in the question What actually determines the angular uncertainty of the source of a detected gravitational wave?

  • Determine the position, parallax, and annual proper motion of 1 billion stars with an accuracy of about 20 microarcseconds (µas) at 15 mag, and 200 µas at 20 mag.

20 (µas) is about $1 \times 10^{-10}$ radians. If the Earth's amplitude is 2 AU, then the farthest distance that could be detected is $2 \times 10^{10}$ AU.

If you want to measure to about 10% accuracy, then that distance is $2 \times 10^{9}$ AU or about 3,000 30,000 light years.

That sounds surprisingly far away!

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    $\begingroup$ But 20 microarcsec is not the most accurate parallax available. $\endgroup$ – Rob Jeffries May 1 at 16:39
  • $\begingroup$ 3000 ly is a long way compared with going to the chemist down the road, but is a fraction of the size of even our puny galaxy. $\endgroup$ – Carl Witthoft May 1 at 19:30
  • $\begingroup$ @RobJeffries I'll try to investigate further then, thanks! I suppose I should look into VLBI as well. $\endgroup$ – uhoh May 1 at 22:34
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    $\begingroup$ Yes VLBI is the record holder I think - as discussed in the closely linked question. In your answer, I note that a 200 $\mu$as parallax would be measured with 10% precsion. This corresponds to a distance of 5000 pc or $\sim$ 15,000 light years. $\endgroup$ – Rob Jeffries May 2 at 10:02
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    $\begingroup$ Parallax is based on a triangle with a base of 1 au. $\endgroup$ – Rob Jeffries May 2 at 10:15

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