Proxima Centauri can't explode as supernova as it is about 2 orders of magnitude too small and light.
But if a supernova were to happen from that distance? How bright would it be?
You can use the formula:
$$\text{Apparent magnitude} = \text{Absolute magnitude}+5log_{10}(distance)-5$$
where the distance is in parsecs.
Proxima centauri is 1.3 parsecs distant.
A supernova typically has an absolute magnitude between -15 and -19 (although they can go brighter or dimmer in the case of hypernovas etc). So Let's use -15 as the low end and -19 as the high end.
Plugging into the equation, we get an apparent magnitude of between -18 and -23.
For comparison, the sun as seen from earth has an apparent magnitude of about -26, so the supernova would be between 1500 and 15 times dimmer than the sun from earth.
Perusing the list in the Wikipedia article on apparent magnitude, we find the brightness of the supernova would be between the brightness of the Sun viewed from Jupiter and the Sun viewed from Pluto. In any case, that is plenty of light to read by, and plenty of light to see colour by.