1
$\begingroup$

I saw that Black Holes can evaporate because of Hawking radiation. Because pair of particle, antiparticle can spawn at any point of the space, the antiparticle could be absorbed by the black hole and the particle go outside of it, like if the black hole where "lightning".

But, if one element of the pair can be absorbed by the black hole, isn't there an equal probability of that the particle will be absorbed to ?

I could imaginate that the probability of fluctuation of going into 0 with an equal probability of +1 or -1 mass over time is nonnull, also that's why black hole could evaporate... Or something like it ?

| improve this question | |
$\endgroup$
-1
$\begingroup$

I cannot show this or prove it but the main idea, in simplest terms, is that a matter-antimatter pair, near the event horizon, will form. A member of this pair will decay back into the event horizon and be absorbed by the black hole. The other particle will decay out into the free space.

| improve this answer | |
$\endgroup$
  • $\begingroup$ This is inaccurate - especially “The other particle will decay out into the event horizon and then on into space.” If it “decays” into the event horizon it disappears into the BH. You also fail to explain why a virtual particle falling into the BH makes it lose mass instead of gaining mass. Nor why the effect isn’t cancelled out by the virtual pairs forming just inside the EH. Sometimes simple answers can be too simple :-) $\endgroup$ – Chappo Hasn't Forgotten Monica Dec 16 '19 at 12:38
  • $\begingroup$ @ChappoSaysReinstateMonica. I changed my answer somewhat. If its still wrong I will delete it. But if you know its wrong I encourage you to answer the question yourself. $\endgroup$ – jmh Dec 16 '19 at 23:38

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.