Why does the Hubble flow does not carry photons with it?

I have this naive question. We know that the expansion of the universe "takes" or "carries" the galaxies with it, separating them, but this doesn't apply to photons. My guess is that it has to do with the fact that photons are massless (i.e. they always move with c), but I am not sure and would like a more physical explanation or insight.

• Why do you say "this doesn't apply to photons"? From astronomy.stackexchange.com/a/39379/16685 "The hitherto most distant observed galaxy, GN-z11, has a redshift of $z=11.09$. It was only $2.7\,\mathrm{Glyr}$ from us when it emitted the light we see today, but in the $13.4\,\mathrm{Gyr}$ it took the light to reach us (most of the age of the Universe), GN-z11 moved out to a current distance of $32.2\,\mathrm{Glyr}$!" – PM 2Ring Oct 18 at 23:45
• Thank you, good way to see it! – xkudsraw Oct 22 at 15:44

• @ChappoHasn'tForgottenMonica As I said, it's a very common misconception. I know Davis & Lineweaver missed it; they aren't infallible. As usual in GR it's a result of treating coordinates as though they have physical meaning. It's the same thing that leads people to think that it takes forever to cross an event horizon, etc. The Milne model is a good source of counterexamples to misconceptions about cosmology, like Rindler coordinates are with event horizons. In the Milne model $a(t)\propto t$, but it's just Minkowski space. You can show cosmological and SR redshifts are equal, etc. – benrg Oct 19 at 0:55