# What is the Milne-Eddington Approximation?

In this paper: Planet temperatures with surface cooling parameterized it states in the "radiation model" the following:

The Eddington–Milne approximation relates $$T_0$$ and $$T_e$$ through the gray IR optical depth $$\tau$$:

$$T_0=T_e(1+\frac{3}{4}\tau)^{0.25}$$

I looked this approximation up on google, and found it was more commonly known as the Milne-Eddington Approximation. However, this approximation seems to (mainly) be applied to stars, and I can't exactly see the connection between it and the temperature of a planet. (I also don't completely understand what an "optical depth" is.)

What is this approximation and why can it be applied to approximate the temperature of a planet with an atmosphere?

• The optical depth is "a measure of how opaque a medium is to radiation passing through it" which intuitively means relates to how far you can see into the atmosphere from outside for a given wavelength. I am stumbling upon the "gray" in your quote though - is "gray IR" a commonly accepted term? Apr 20 '21 at 20:07
• "Gray" opacity or optical depth generally means "wavelength-independent", i.e. it is assumed to be the same at all wavelengths. I haven't seen it used to modify IR before, but from context I take it to mean the assumption of a constant optical depth across some limited range of wavelengths, here the infrared (or part of it - the IR is huge as a part of the EM spectrum!) Apr 22 '21 at 1:24
• @eshaya I did find another source that indeed had 1/2 instead of 1. Do you have a source that derives the equation? Apr 22 '21 at 17:39

$$F_{\rm rad} = \frac{c}{3\rho \kappa_R} \nabla E_{\rm rad}$$
Then you can couple the equations for $$\rm E_{rad}$$ and $$\rm E_{gas}$$, integrate and solve for $$\rm E_{gas}$$, which is $$\rm \rho c_vT$$. This gives you the ME relation, which is valid for the diffusive radiative transport in gases, and precludes interesting things like the greenhouse-effect, temperature inversions, etc.