For a planet like the Earth, it is reasonably straightforward to show that the tidal acceleration across the planet is around $1g$ at the innermost stable circular orbit (ISCO) of a $\sim 10^8 M_\odot$ black hole (i.e. an orbit of 3 Schwarzschild radii in size).
Since a person is about 1/6400000 of the extent of the planet, then stretching acceleration they experience, which is proportional to the extent of an object, will be just $1/6400000$ of $1g$. This would not be felt.
If you orbit a less massive black hole at its ISCO, then the tidal forces get bigger. But the planet would then be ripped apart, because that's what happens if the tidal acceleration exceeds the surface gravity. There is no configuration where you can stand on an intact planet (of a sensible size) and experience a direct tidal force.
If you are standing on a planet that falls toward a black hole, the planet will disintegrate before you begin to feel any tidal stretching.
In fact it is also a straightforward calculation to show that, for a free falling person, the time from when the stretching becomes noticeable to reaching the singularity is of order a few tenths of a second; about the time it takes sensations to reach and be processed by the brain, irrespective of the black hole mass.