3
$\begingroup$

The radius of a rocky planet like earth is fairly easy to define based on the fact that the ocean's surface is fairly smooth, and it is a natural point to measure. Other planets like Mars, the surface is clear and I suppose the radius to the highest peak divided by the radius to the lowest valley is probably close enough to 1 that it doesn't matter too much.

However, larger planets and stars that are primarily composed of gas, where the density of the gas is presumably a smooth change from high to low, where is the "outside" of such a planet (or star) considered to be? Wikipedia says that the equatorial radius of Jupiter is 71,492 km, which is a fairly precise measurement. So if I were to travel to Jupiter what exactly would I find 71,492 km from the center?

$\endgroup$
2

1 Answer 1

3
$\begingroup$

Mark Adler's answer to What defines the radius of a ball of gas like Jupiter? in Space SE says:

The radius of Jupiter and the other gas giants is defined, somewhat arbitrarily, to be the radius at which the atmosphere has a pressure of 1 bar. As your question points out, they had to pick something. So that's what they picked. This convention is used for all of the gas giants in our solar system.

However, as ProfRob points out

This definition of planetary radius only applies to planets in our own Solar system.

or really to planets for which we have good atmospheric models due to a variety of detailed observations and measurements made possible by their proximity.

I am not sure if there are accepted definitions of size for exoplanets.

For those observed photometrically (by the depth of the "dip" in the light curve when they cross the faces of their stars) the inferred size will be based on opacity - what diameter occulting disk would produce the same size dip, and for those observed spectroscopically (by the doppler shift of the stars spectral features as it moves around the center of mass of the star and the planet) a size would have to be inferred from the mass based on some model or theory for exo-solar system evolution.

And...

The radius of the Sun used to be defined by opacity (at an optical depth of 2/3). That photosphere radius has some measurement interpretation issues, and remains a subject of investigation. Apparently the IAU got tired of it, so in 2015 the "nominal" radius of the Sun was defined to be exactly 695,700 km. This allows the use of "solar radii" as a unit without everyone wondering what radius to use to convert that to distance units.

While the unit "solar radii" is fixed, I think the photosphere (opacity = 2/3) would be a better choice if comparing stars in conversation. That way you can get a polar and equatorial radius and get an oblateness.

We should source our answer assertions - in this case this user is treated as an an expert in the field of space and planetary exploration over in Space SE.

For more on the Sun's photosphere and it's radius and other things:

$\endgroup$
2
  • 1
    $\begingroup$ Great answer from Space SE, thanks for helping me find it and for all the links. $\endgroup$
    – Fraser Orr
    Jun 4, 2023 at 1:38
  • $\begingroup$ @ProfRob Yes great point! I've updated accordingly, how's that? $\endgroup$
    – uhoh
    Jun 4, 2023 at 8:22

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .