8
$\begingroup$

This is the article as mentioned above: The Maximum Mass of a Neutron Star is 2.25 Solar Masses

To repeat, according to this article, the maximum mass of a non-rotating neutron star is around 2.5-3 solar masses.

  1. What is defined as a non-rotating neutron star? I find it difficult to understand how any such body could not rotate, based on the conservation of energy principle.

  2. Secondly, is the possible maximum mass of a rotating neutron star greater than this value range for a non-rotational body?

  3. According to the article, if I understand correctly, a non-rotating neutron star of greater than this mass will turn into a black hole, albeit one of the smallest mass.

$\endgroup$
1
  • 6
    $\begingroup$ "What is defined as a non-rotating neutron star?" is sort of like asking "what is defined as a vacuum?", or "what is defined as absolute zero?". The lack of real, absolute examples of an ideal, should not prevent understanding the meaning of the ideal. $\endgroup$ Commented Mar 16 at 19:46

2 Answers 2

18
$\begingroup$

The paper (arXiv version) actually finds a mass limit of $M_{\mathrm{TOV}}=2.25^{+0.08}_{-0.07}M_{\odot}$; it is believed that above this limit, subject to some caveats, a neutron star would further collapse into a black hole. The range $M\sim2.5\mathrm{-}3M_{\odot}$ really refers to compact objects that have been detected in gravitational wave events; they're mentioned just to indicate that according to the analysis, they are in fact likely the lowest-mass black holes known. LIGO/Virgo gravitational wave data alone could not determine whether that class of objects are neutron stars or black holes.

"Non-rotating" really does mean non-rotating. The equation governing models, the Tolman-Oppenheimer-Volkoff equation, assumes the star is not rotating. Since we would expect all neutron stars to rotate to some degree, and since the paper is based on a selection of real neutron stars, it might appear the data isn't applicable! However -- and this is a point the paper and articles maybe don't emphasize enough -- most reasonable spin periods do not significantly change the mass limit of a neutron star. For all but the fastest-spinning neutron stars, the difference would not be more than a percent or so (Alsing et al. 2018), and it is only for the very shortest possible spin periods that we would see deviations of up to 20% (Breu & Rezzolla 2016). No known pulsars spin fast enough to change the limit by more than ~2%.

The authors therefore assume that most of the neutron stars in the sample can be modeled as slow rotators. Three (PSR J0952-060, PSR J2215+5135, and PSR J0740+6620) have short enough rotation periods that an adjustment must be made, which they do using relations derived from simulations. They therefore believe the results are valid.

For what it's worth, since the paper's computed uncertainties on the mass limit are ~4%, any variation due to rotation among the other neutron stars in the sample is a factor of a few less, and those uncertainties dominate. It certainly doesn't affect their conclusion regarding the type of objects in the $2.5\mathrm{-}3M_{\odot}$ range.

$\endgroup$
2
  • 1
    $\begingroup$ Just a note. The fastest rotating pulsar is already only at about 1/3 of the Keplerian limit. So the formulae in Breu & Rezzolla suggests the TOV limit is ony increased by 2% at most. $\endgroup$
    – ProfRob
    Commented Mar 18 at 12:32
  • $\begingroup$ @ProfRob Thanks, my language in the second paragraph was not ideal; I should have made it clear that the last sentence was referring to models and not specific pulsars. $\endgroup$
    – HDE 226868
    Commented Mar 22 at 14:35
9
$\begingroup$

HDE226868's answer is fine and I won't repeat that. However, an answer to your headline question is that a non-rotating neutron star is effectively one where the rotation does not significantly alter the structure.

A criterion to decide if rotation is important is to compare the angular acceleration with the gravitational acceleration at the surface. Rotation is unimportant if $$ r \omega^2 = \frac{4\pi^2 r}{P^2} \ll \frac{GM}{r^2}\ $$ and thus $$P^2 \gg \frac{4\pi^2 r^3}{GM}\ , $$ where $r$ and $M$ are the neutron star radius and mass, and $P$ is the rotation period. Putting some numbers in $$ P \gg 0.0004\left(\frac{M}{2M_\odot}\right)^{-1}\left(\frac{r}{10{\rm km}}\right)^3 \ {\rm seconds}\ .$$

Since the fastest spinning pulsar has a period of 0.0014 s and since the vast majority of neutron stars spin down to much slower periods than 1 s very early in their lives, then rotation is going to be unimportant in almost all cases for neutron stars.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .