New answers tagged distances
2
Judging by the fact that after cubing the distance you have ended up with an exponent of 1021 (21 = 6×3+3) at the first point you have substituted the numbers into the equation, you appear to be assuming that 1 km3 is 1000 m3. However, if you write the same linear quantity in metres and kilometres and cube them, you can see this is not ...
5
Here's how I would do it. I'd convert everything to a single, standard set of units as recommended in the comments, and also stick to one digit before the decimal in scientific notation:
$$ T^2=\frac{4\pi^2r^3}{G\cdot M_{Sun}}$$
Using all numbers in the same units:
$r \ 4.5 \times 10^{11} \ (m) $
$G = 6.674 \times 10^{-11} \ (m^3 \ kg^{-1} s^{-2}) $
$M ...
6
According to Oxford Dictionary of English, the word "modulus" is the diminutive of the Latin modus, meaning measure (modus, in turn, comes from Proto-Indo-European mod-os, Nocentini & Parenti 2010.
Hence, the distance modulus is a "measure of distance", just like the modulus of a vector is a way of measuring its size, and Young's modulus is a way of ...
5
The axis type ‘FELO’ is regularly gridded in frequency but expressed in velocity units in the optical convention. The unit here is $m/s$.
This means that the wavelength/frequency has already been expressed as velocity corresponding to a Doppler shift around a reference wavelength. This velocity is given by
$$
v = c \ \frac{\lambda - \lambda_0}{\lambda_0 ...
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