New answers tagged

8

The brightness of a Solar System object, seen in reflected light, depends on how far it is from the Sun, $d_s$, and how far away it is from the observer, $d_o$, (and the angles between them). Both dependencies are "inverse square laws": $${\rm brightness} \propto \left(\frac{1}{d_s^2}\right)\left(\frac{1}{d_o^2}\right)\ . $$ Both Uranus and Neptune ...


-2

If I have calculated it right then the apparent magnitude of Neptune as seen from Uranus is approximately 4. The absolute magnitudes of Neptune (-7.11) and Uranus (-7.00) are nearly identical. The apparent magnitude of Uranus is 5.38. The distance between Neptune and Uranus is roughly half of the distance between Earth and Uranus. At half the distance a ...


Top 50 recent answers are included