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Proxima Centauri can't explode as supernova as it is about 2 orders of magnitude too small and light. But if a supernova were to happen from that distance? How bright would it be? You can use the formula: $$\text{Apparent magnitude} = \text{Absolute magnitude}+5log_{10}(distance)-5$$ where the distance is in parsecs. Proxima centauri is 1.3 parsecs ...


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Observed brightness (or magnitude) depends on the distance between the source and the observer. The further the distance, the fainter we will observe given the same source. If the distance r1 is measured between the source and the observer given the accelerating universe, then the distance r2 measured given the decelerating universe would be r2 < r1. ...


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