I mean in intrinsic detail. What would happen to our bodies besides "burst into flames"?
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8$\begingroup$ You should land at night, of course. $\endgroup$– gerritCommented Sep 30, 2015 at 11:05
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1$\begingroup$ Wouldn't one be dead ,long before even reaching the Sun, from heat and radiation ? $\endgroup$– Peter UCommented Sep 30, 2015 at 15:09
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$\begingroup$ @gerrit WT? What do you mean? There is no Sun at night, the Sun disappear in the twilight and only appears in the dawn... $\endgroup$– EProgrammerNotFoundCommented Oct 2, 2015 at 1:43
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2 Answers
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Well first thing's first: You would disintegrate. At the temperature of the Sun, most of the molecules that make up our bodies could not even survive, that is why we would not only fry and die, we would really disintegrate (all the molecules breaking apart, leaving only loose atoms).
Let's now pretend heat doesn't exist. This is what would happen. First, we must remember that there is no solid surface to the Sun just like there is no surface to Uranus.
As soon as you reached the Sun itself, you would sink. The sun's density is less than 1 — and 1 is the density of water. So you would be sucked inside kind of. Except that there are convection currents. If we happen to be just above one, we might be kept close to the surface.
But, eventually, the eddies would entrain us sideways until we came to a "downdraft" that would take us downwards.
Anyway, let's talk about gamma rays now. Gamma rays are a form of light.
So even though heat is out of the way, all of these light rays are now trying to tear up whatever remaining molecules we have. This could trigger nuclear reactions.
Eventually, you (not me, I'm out of there) would cycle between two layers, in a convection cell moving you up and down, above and below the depth where the density of the gas is the same as the density of your body.
So I guess there's one sure thing about all of this.
You're going to need some sunscreen.
answered Sep 29, 2015 at 20:44
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3$\begingroup$ Assuming you have some kind of space suit made of unobtainable and you could survive the heat and gamma rays, the gravity on the surface of the sun is 28 times that of earth. If one of those up-drafts held you reasonably aloft, the gravity would crush you even in an indestructible suit. Humans can't survive 28 Gs for long. This would feel like more wind than you could ever experience on Earth, it would be quite the wild ride, for the half second you'd survive that is. :-) $\endgroup$– userLTKCommented Sep 30, 2015 at 4:42
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2$\begingroup$ If no updraft, you'd fall faster than you can imagine falling on earth. In 1 second on earth, you fall 16 feet. 1 second into the sun you'd fall nearly 450 feet, minus plasma resistance, of-course. As the plasma resistance slowed you down, you'd begin to feel the suns g forces again and get crushed again. The only way to really survive it would be a space ship (sun ship?) that flies through the sun very very fast at near orbital velocity, as this would counteract the gravity problem. We don't have that technology yet. (love your answer by the way Pies). $\endgroup$– userLTKCommented Sep 30, 2015 at 4:46
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3$\begingroup$ Looks like we'd fall about halfway to the core before reaching neutral bouyancy: th.physik.uni-frankfurt.de/~scherer/Blogging/StandardSolarModel/… Of course, the graph gives no indication of what figure they're using for the suns's diameter. $\endgroup$ Commented Sep 30, 2015 at 9:10
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$\begingroup$ How does gamma ray radiation cause a nuclear reaction? $\endgroup$ Commented Jun 12, 2021 at 21:49
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Even if you could withstand the conditions (pressure, temperature, radiation, charged particles, magnetic field, gravitational crunch) on the 'surface' of the Sun, you cannot step onto the Sun: it has no surface. But why does it appear to have a sharp edge?
The Sun is a ball of hot plasma permeated with magnetic fields and photons (=electro-magnetic radiation). The photons are permanently absorbed and re-emitted, whereby transporting energy from the Solar depths (another transport process is convection). To very good approximation, the photons follow a black-body spectrum with the temperature equal to that of the ambient gas.
Now, the image of the Sun that we perceive is made from those photons that managed to escape unscathed. The likelihood for a photon coming from a certain depth and escaping the Sun decreases exponentially with depth $d$ as $\mathrm{e}^{-d/\tau}$ with optical depth $\tau$. Since $\tau\ll R_{\odot}$, the radius of the Sun, the Sun appears to have a sharp edge. The same also applies to gas planets: you cannot step onto them, but would sink.
